Gates and Circuits
Entanglement and Bell states
Correlations with no classical explanation, no signaling
Two bits can be correlated the boring way: write the same value into both, seal them in envelopes, mail them apart. Open one, you know the other. A Bell pair is correlated in a way that has no such story. The two qubits are not secretly carrying preset values, yet they agree perfectly the instant you look. And despite decades of hype, that agreement cannot carry a single bit of message. Both of those claims need care, so we build them slowly.
The myth to drop first
The most stubborn misreading of entanglement is that measuring one qubit instantly transmits something to the other, a spooky telephone across any distance. Test the intuition before the math.
Alice and Bob each hold one qubit of a Bell pair, light-years apart. Alice measures hers. Can she use that to send Bob a message faster than light?
See the correlation, then try to break it
The widget builds a Bell pair with an H and a CNOT, then samples it. Watch the joint outcomes lock together while each qubit alone stays a fair coin. Then act only on the first qubit and confirm the second qubit's own statistics never move.
Measure the pair many times to see the correlation, then try to signal by changing the first qubit's gate.
Why the Bell state cannot be split
We built from last lesson. A state is when it cannot be written as one qubit's state another's. Suppose, for contradiction, that it could:
Matching terms forces (there is an ) and (there is an ), but also and (no or ). From , either or , and either one kills or . Contradiction. No product of two single-qubit states reproduces this vector.[1] The two qubits genuinely have no separate states of their own, which is the mathematical content of entanglement, derived rather than asserted.
Perfectly correlated, individually random
Where the no-signaling wall comes from
Here is why the perfect correlation still sends nothing. Consider only Bob, holding the second qubit. Before he compares with Alice, his outcome is half the time and half the time, and this is true whether or not Alice has measured, and whatever local gate Alice applied first (the widget let you check X and Z). His local statistics are frozen at 50/50. A message needs a detectable change on the receiving end, and there is none. Only when Alice and Bob bring their two lists of outcomes together, over an ordinary channel no faster than light, do the correlations appear. Entanglement is a shared correlation you can only cash in by comparing notes, never a channel.
What entanglement is not is a hidden set of preset values. Bell's theorem (which we name rather than prove here) shows no assignment of secret local values can reproduce the full pattern of quantum correlations across different measurement choices. The correlations are stronger than any envelope story allows, and experiments have confirmed the quantum prediction.[2] This is the resource that powers teleportation and quantum key distribution, and it is why the no-cloning theorem has teeth.
from qiskit import QuantumCircuit
from qiskit.quantum_info import Statevector
qc = QuantumCircuit(2)
qc.h(0)
qc.cx(0, 1) # Bell state (|00> + |11>)/sqrt(2)
probs = Statevector(qc).probabilities_dict()
# {'00': 0.5, '11': 0.5} joint: only matching outcomes
marginal_q1 = Statevector(qc).probabilities([1])
# [0.5, 0.5] qubit 1 alone: a fair coin, carries no messageLock it in
- Entangled means the joint state does not factor into a state per qubit; the parts have no independent state.
- A Bell pair is perfectly correlated (see 0 on one, the other is 0) yet each qubit alone measures 50/50.
- No-signaling: a local operation on one qubit leaves the other qubit's own statistics unchanged, so entanglement carries no faster-than-light message.
- The correlations are stronger than any preset-value story allows (Bell's theorem), which is what makes entanglement a genuine resource.
Recall: define entangled operationally, and explain why a Bell pair cannot transmit information.
The definition plus the no-signaling argument in one breath. Try to state it, then check.
You measure the first qubit of (|00> + |11>)/root2 and get 0. What is the second qubit?
Why can entanglement not be used to send a message?
Match each term to its meaning.
Factors into a state for each qubit.
Does not factor; qubits have no separate state.
A maximally entangled pair like (|00> + |11>)/root2.
Local outcomes are unchanged, so no message crosses.
Primary source
Quantum Country, Quantum computing for the very curiousThe entanglement section works through exactly this non-factorability argument and the individually-random, jointly-correlated behavior, with recall prompts that make the counterintuitive parts stick.
Sources